Question

A substance is heated from 15 degree Celsius to 18 degree Celsius by providing heat of 270 cal.lf mass of substance is 3 kg,then determine the specific heat​

Answer 1

energy(q)=270 cal

               =1129.68j

mass(m)=3kg

difference in temperature(Δt)=18-15

                                                =3°c

                                                =3K

specific heat capacity = c

          q = mcΔt

1129.68 =3*c*3

c =1129.68/9

  =125.52J/K