Question

. A substance, on analysis, gave
the following percent composition:
Na = 43.4 %, C = 11.3 % and
O = 45.3 %. Calculate the empirical
formula. (At. mass Na = 23 u, C = 12
u, O = 16 u).

Answer 1

Answer:

Na2CO3.

I think these answer is correct...

Answer 2

Answer:

Na2 CO3

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