A substance reduces to 1/6 th of its original mass in 2 hours. The half life period of the substance will be :
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if it is first order reaction then
k = 1/2×[ln(6)] hours^-1
half life = ln2/k
= 2ln2/ln6
k = 1/2×[ln(6)] hours^-1
half life = ln2/k
= 2ln2/ln6
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