Question

A substance weighs 8 g in air and 6 g in water of
density 1 g cm-. The density of substance in g cm-3 is :
(a) 8 (6) 4 (c) 2
(d) 1.
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Answer 1

Answer:

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Answer 2

Answer:

(B)The density of the object is

$\rho _{obj} = 4 \: gm \: cm {}^{ - 3}$

Explanation:

Given that,

The weight of the substance in air is 8gm

$= > w_{a} = 8 \: gm$

Also given,The weight of the substance in water is 6gm

$= > w_{w} = 6gm$

Density of the object can be found using relation

$\frac{ρ _{obj} }{ρ _{w}} = \frac{w _{a}}{w _{a} - w _{w}}$

Substituting the known values,we get

$\frac{\rho _{obj}}{1} = \frac{8}{8 - 6} = > \rho _{obj} = 4 \: gm \: cm {}^{ - 3}$

Therefore,the density of the object is

$\rho _{obj} = 4 \: gm \: cm {}^{ - 3}$

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