A substance with a mass of 10 kg gains 106.5 kj of heat when its temperature increases 15°c. what is this substance's specific heat?
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Mass = 10kg (Given)
Q= 106.5KJ (Given)
Q = m SΔT
ΔT= 15°C
M = 10kg
Therefore,
106.5×10³ = 10kg×15°C.S
On re-arranging,
S = 106.5 ×10³/10×15 J/kg-C
On solving,
S = 710J/kg-C
Thus substance's specific heat = 710J/kg-C
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