Question

a. Subtract 5x²y + 2xy²-3xy-7x² + 1 from -3x'y + 9xy²-4xy + 5x²-13.​

Answer 1

Step-by-step explanation:

$= - 3 {x}^{2} y + 9x {y}^{2} - 4xy + 5 {x}^{2} - 13 - (5 {x}^{2} y + 2x {y}^{2} - 3xy - 7 {x}^{2} + 1 ) \\ = - 3 {x}^{2} y + 9x {y}^{2} - 4xy + 5 {x}^{2} - 13 - 5 {x}^{2} y - 2x {y}^{2} + 3xy + 7 {x}^{2} - 1 \\ = - 8 {x}^{2} y + 7x {y}^{2} - xy + 12 {x}^{2} - 14 \: (answer)$

Answer 2

Hey your answer is:

Step-by-step explanation:

=-3x^2y+9xy^2-4xy+5x^2-13-5x^2y-2xy^2+3xy+7x^2-1

=-8x^2+7xy^2-xy+12x^2

Hope it helps u