Physics, asked by prernavlko3636, 1 day ago

A sugar solution in a tube of length 2.0 dm produces optical rotation of 12º. Then, the sugar solution is diluted to onehalf of its initial concentration. If the dilute solution is contained in another tube of length 3.0 dm, the optical rotationproduced by it will be:​

Answers

Answered by satyamkrsingh2000
0

Answer = 9°

Explanation:

Attachments:
Answered by shivamvishwakarma6b
0

Answer:

In first case, θ=Sl

1

C

1

In second case, θ

=Sl

2

C

2

l

1

=0.2m and l

2

=0.3m

The solution in the first tube is passed to another tube of 0 m length, so if volume of the first tube is v

1

and second tube is v

2

and if radius of both tubes are r, then

v

2

=0.3×πr

2

=(0.2+0.1)×πr

2

=

2

3v

1

Using proportional sets to calculate concentrations of solution.

C

1

v

1

=C

2

v

2

C

2

=

3

2C

1

Hence, θ

=Sl

2

C

2

=S×0.3×

3

2C

1

=S×0.2×C

1

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