Question

A sugar solution with a mass of 200 grams has a percent by mass concentration of 25%. How much of the sugar and water is present in this solution?​

Answer 1

Answer:

600 gram of Sugar and Water is present in the sugar solution.

Explanation:

Let the total amount of sugar solution be x,

Equation formed:

$25\% \: of \: x = 200 \\ \frac{25}{100} \times x = 200 \\ \frac{x}{4} = 200 \\ x = 200 \times 4 = 800 \: g$

Amount of sugar solution excluding mass = 800 g - 200 g = 600 g

Hence, 600 g of Sugar and Water is present in the sugar solution.

Answer 2

Given:

Mass percent of sugar in solution = 25%

Total mass of solution = 200 g

To find:

Mass of sugar/mass of solute = ?

Step wise explanation:

Mass of solute is the amount of solute present in solution in grams.

The mass percent of a solution tells how concentrated the solute is or how much solute is present per 100 grams of solution.

Mass of solute can be calculated by rearranging following equation:

Mass percent of solute = mass of solute (g) ÷ mass of solution (g) × 100

Therefore to find the mass of a solute:

Let "x" be the mass of sugar

∴ 25 ÷ 100 = x ÷ 200

x = 25 × 200 ÷ 100

x = 25 × 2

x = 50 grams

Hence, mass of sugar in the given solution is 50 grams.