Question

a sugar syrup of mass 214.2 gram contains 34.2 gram of sugar calculate the concentration of sugar in the syrup b) what is the solution?​

Answer 1

(i) Molal concentration = Molality

= Moles of solute/Mass of solvent in Kg

(ii) Mole fraction of sugar

= Moles of sugar/Total moles in solution

(i) Weight of sugar syrup = 214.2 g

Weight of sugar in the syrup = 34.2 g

∴ Weight of water in the syrup = 214.2 – 34.2 = 180.0 g

Mol. wt. of sugar, C12H22O11 = 342

∴Molal concentration = 34.2 *1000/342 *180 = 0.56

(ii) Mol. wt. water, H2O = 18

∴ Mole fraction of sugar = 34.2/342 /180/18+34.2/342

= 0.1/10+0.1 = 0.1/10.1 = 0.0099

Answer 2

Explanation:

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