a sugar syrup of weight 214.2 gm contains 34.2 g of sugar Calculate Molal concentration and mole fraction of sugar
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sugar formula = C12H22O11
molar mass = 12*12 +1*22+16*11 = 342
no. of moles of solute = 34.2/342 = 0.1
mass of solvent = 214.2 - 34.2 = 180gm =0.18kg
molal concentration = 0.1/0.18 = 0.555m
mole fraction = 34.2/214.2 = 0.1596
molar mass = 12*12 +1*22+16*11 = 342
no. of moles of solute = 34.2/342 = 0.1
mass of solvent = 214.2 - 34.2 = 180gm =0.18kg
molal concentration = 0.1/0.18 = 0.555m
mole fraction = 34.2/214.2 = 0.1596
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