Question

A sugar syrup weight of 214.2 grams contains 34.2 grams sugar calculate molarity
Molality and mol fraction

Answer 1

Explanation:

(i) The molal concentration is, 0.55 mole/Kg

(ii) Mole fraction of sugar in the syrup is,

Solution for part (i) :

Molality : It is defined as the number of moles of solute present in one kilogram of solvent.

Solute = sugar

Solution = sugar syrup

Solvent = water

First we have to calculate the mass of solvent.

Mass of solvent = Mass of sugar syrup - Mass of sugar = 214.2 - 34.2 = 180 g

Now we have to calculate the molality.

Therefore, the molal concentration is, 0.55 mole/Kg

Solution for part (ii) :

Now we have to calculate the moles of solute and solvent.

Now we have to calculate the mole fraction of sugar in the syrup.

Therefore, the mole fraction of sugar in syrup is,

9.90★10^-3

Answer 2

Answer:

The mole fraction of sugar is

9.90×10^-3