A suitcase is gently dropped on a conveyor belt moving at 3m/s. if the coefficient of friction between the belt and the suitcase is 0.5. find the displacement of suitcase relative to conveyor belt before the slipping between the two is stopped
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Answered by
52
Answer:0.9m
Explanation:
f=umg,
a=ug
a=0.5*10= 5m/s^2
V^2=u^2+2as
0^2=3^2+2*5*s
-10s=9
s=-9/10 =0.9m as distance can't be negative
Answered by
19
Answer:0.9m
Explanation:
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