Question

A suitcase of measures 55 cm x 35 cm x 12 cm is to be covered with a tarpaulin cloth. How many metres of
terpaulin of width 70 cm is required to cover 140 such suitcases?​

Answer 1

Given :-

• Dimensions of suitcase = 55 cm × 35 cm × 12 cm
• Length (l) = 55 cm
• Breadth (b) = 35 cm
• Height (h) = 12 cm
• Width of terpaulin (b') = 70 cm

To Find :-

• Length of terpaulin (l') required to cover 140 such suitcases = ?

Solution :-

Total area of terpaulin = 140 × Total Surface Area of suitcase

⇒ l' × b' = 140 × 2(lb + bh + hl)

⇒ l' × 70 = 140 × 2[(55 × 35) + (35 × 12) + (12 × 55)]

⇒ l' × 70 = 140 × 2[1925 + 140 + 660]

⇒ l' × 70 = 140 × 2 × 3,005

⇒ l' = $\dfrac{140*2*3005}{70}$

⇒ l' = 12,020 cm

Now we change the unit.

100 cm = 1 m

⇒ 1 cm = $\dfrac{1}{100}$ m

⇒ 12020 cm =  $\dfrac{1}{100}$ × 12,020 m

⇒ 12020 cm =  $\dfrac{12020}{100}$

⇒ 12020 cm = 120.2 m

∴ 120.2 m of terpaulin is required to cover 140 such suitcases.