Question

A suitcase of measures 55cm*35cm*12cm is to be covered with a trapulin cloth. How many metres of trapulin of width 70cm is required to cover 150 such suitcases?

Answer 1

Hope it would be useful...

Answer 2

128.7879 metres of trapulin of width 70 cm is required to cover 150 such suitcases.

Step-by-step explanation:

Given:

Here a suitcase of measures $(55cm\times 35cm\times 12cm)$

Total surface area of suitcase = 2[(55) (35) + (35) (12) + (55) (12)]

                                                    = 2[1925 + 420 + 660]

                                                    = 2[3005]

                                                    = $6010 cm^2$

Total surface area of 150 suitcases = $150 \times 6010$

                                                             = $901500 cm^2$

Required tarpaulin = $Length \times Breadth$

$901500 cm^2 = Length \times 70$

$Length = \frac{901500}{70}$

                   = 12878.57 cm.

Length = $\frac{12878.57}{100}$ m.

              = 128.7879 m           

Hence 128.7879 metres of trapulin of width 70cm is required to cover 150 such suitcases.