Question

A suitcase with measure 80cm×48cm×24cm is to be covered with a tarpaulin cloth.How many meters of trampaulin of width 96cm is required to cover 100 such suitcases?

Answer 1

The suitcase
l = 80 cm
b = 48 cm
h = 24 cm
therefore,
Total Surface Area = 2(lb + bh + lh)
= 2 [(80*48) + (48*24) + (80 * 24)]
= 2 (3840 + 1152 + 1920)
= 2 * 6912
= 13824 cm^2

Length of cloth required = (area of suitcase/ breadth) * 100
= (13824/ 96) * 100
= 144 * 100
= 14400 cm
= 14400 /100 m
= 144 m

Answer 2

Given,

Measures = 80 cm × 48 cm × 24 cm

The suitcase is in cuboid shape.

We know,

Surface Area of Cuboid = 2(lb + lh + bh)

                                      = 2 (80 x 48 + 80 x 24 + 48 x 24)

                                      = 2(3840 + 1920 + 1152)

                                      = 2 x 6912 

                                      = 13824

Surface Area of 1 Suitcase = 13824

∴ Surface Area of 100 suitcases =13824 × 100 cm²

                                                    = 1382400 cm²

Now, Required length of tarpaulin = Area/width  [tarpaulin have same area]

                                                      = 1382400/96

                                                      = 14400 cm 

It is given how many meters. So length in meters = 144 meters