Question

A suitcase with measures 100 cm × 62 cm × 44 cm is to be covered with a
tarpaulin cloth. How many meters of tarpaulin of width 98 cm is required to
cover 100 such suitcases?
pls give me this question answer​

Answer 1

Answer:

272m

Step-by-step explanation:

Total surface area of one suitcase=2(lb+bh+hl)

=2[(100*62)+(62*44)+(44*100)]

=2(6200+2728+4400)

=2*13328=26656 cm²

Surface area of 100 suitcases= 2665600 cm²

Thus, 2665600 cm² of cloth is required,

Let, length of tarpaulin clothes be x,

Then,

(x*98)=2665600

It implies that,

x=(2665600/98)=27200 cm= 272m

Answer 2

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