Question

A SUITCASE WITH MEASURES 160 CM * 96 CM* 48 CM IS TO BE COVERED WITH A TARPAULIN CLOTH.HOW MANY METERS OF TARPAULIN OF WIDTH 192 CM IS REQUIRED TO COVER 200 SUCH SUITCASES?

Answer 1

Surface area of one suitcase is
$2 \times ((160 \times 96) + (160 \times 48) + (96 \times 48)) \\ = 55296 {cm}^{2}$
surface area of 200 suitcase is
$200 \times 55296 = 11059200 {cm}^{2}$
that is the area of the tarpaulin needed is 11059200 cm3
therefore the length of the tarpaulin is

$11059200 \div 192 = 57600cm \\ = 576m$