Question

A suitcase with measures 40 cm ×24cm×12cm is to be covered with a tarpaulin cloth. How many metres of tarpaulin of width 48 cm is required to cover 100 such suitcases?




Answer is 72 metre​

Answer 1

Answer:

Given ⇒

l=48cm,b=80cm,h=24cm

total surface area of cuboid suitcase =2(lb+bh+hl)=2[(48)(80)+(80)(24)+(48)(24)]

=13824cm

2

⟹ Area of 100 suitcases =100×13824cm

2

Area of rectangle tarpaulin =lb

Meters for tarpaulin =

96

13824×100

=14400 cm =144 m

Answer 2

Answer:

Mark me brainlist

Step-by-step explanation:

Let the length of the tarpaulin cloth = x cm

Since, the suitcase is cuboidal in shape,

Total surface of the suitcase = 2(lb + bh + hl) .... (1)

Here, l = 80cm, b = 48cm, h = 24cm

Thus, substituting the values in equation (1) we get,

= 2 [(80 × 48) + (48 × 24) + (24 × 80)] cm²

= 2 [3840 + 1152 + 1920] cm²

= 13824 cm²

Total surface area of 100 suitcases

= 100 × 13824 m²

= 1382400 cm²

Area of the tarpaulin cloth required = Total surface area of 100 suitcases = 1382400 cm²

Area of the required tarpaulin cloth = Length × Breadth

1382400 cm² = x × 96 cm

x = 1382400/96 cm = 14400 cm

x = 144 m