Question

A suitcase with measures 80 cm x 48 cm x 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Answer 1

Answer:

114 m

Step by step explanation:

Measurement of the suitcase = 80 cm × 48 cm × 24 cm

l = 80 cm, b = 48 cm and h = 24 cm

Total surface area of the suitcase = 2[lb + bh + hl]

= 2 [80 × 48 + 48 × 24 + 24 × 80]

= 2 [3840 + 1152 + 1920]

= 2 × 6912

= 13824 cm2

Area of tarpaulin = length × breadth = l × 96 = 96l cm2

Area of tarpaulin = Area of 100 suitcase

96l = 100 × 13824

l = 100 × 144 = 14400 cm = 144 m

Hence, the required length of the cloth = 144 m.

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Answer 2

Step-by-step explanation:

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Given:-

Length of suitcase (l) = 80cm

Breadth of suitcase (b) = 48cm

Height of suitcase (h) = 24cm

Therefore, Area of cloth required to cover 1 suitcase = Total area of 1 suitcase.

___________________________________________________________

Total area of 1 suitcase = Total area of cuboid

= 2(lb + bh + hl)

= 2(80×48 + 48×24 + 24×80)

= 2(3840 + 1152 + 1920)

= 2 × 6912

= 13824 cm^2

___________________________________________________________

Now, we need to find how many metres of tarpaulin of width 96cm is required

to cover 100 such suitcase.

So, Area of the tarpaulin = 100 × Area of 1 suitcase

Tarpaulin is a rectangle with width = 96cm. We need to find length.

Area of the tarpaulin = 100 × Area of 1 suitcase

96 × length = 100 × 13824

$length = 100 \: \times \: \frac{13824}{96} \\ \\ length = 100 \: \times \: \frac{6912}{48} = 100 \: \times \: \frac{3456}{24} = 100 \: \times \: 144$

Length = 14400 cm

$length = 14400 \: \times \: \frac{1}{100} \: m$

Length = 144m

ஃ 144m of cloth is required.