Question

a suitcase with measures 80cm into 48 cm into 24 cm is to be covered with the tarpaulin cloth how many metres of tarpaulin of with 96 cm is required to cover suitcases ​

Answer 1

Answer:

1.44 meters

Step-by-step explanation:

TSA of a cuboid = 2(lb + bh + hl) unit sq.

                           = 2(80*48 + 48*24 + 24* 48)

                           = 2(3840+1152+1920)

                          = 2(6912)

                          = 13824 cm sq.

centimeters cloth required = 13824/96

                                            = 144 cm

1 m = 100 cm

144 cm = 144 cm/100

= 1.44 m

Answer 2

Given: length = 80 cm, breadth = 48 cm and height = 24 cm

To find: how many meters of tarpaulin cloth required to cover 96 cm suitcase.

Step-by-step explanation:

According to question

Total surface area of cuboid = 2(lb+bh+lh)

                                               = $2(80\times48+48 \times 24+24\times80)$

                                               = $2(3840+1152+1920)$

                                               = $2(6912)$

                                               = $13824 cm^2$

Length of tarpaulin cloth required to cover 96 cm suitcase.

                  Area of suitcase = $Length \times Breadth$

                                 $Length = \frac{area}{breadth} \\\\length = \frac {13824}{96}\\\\length= 144cm$

Therefore, 1 cm = 0.01 m

So, 144 cm =  $0.01\times144$ = 1.44 m