A suitcase with measures 80cm X 48 cm X 24 cm is to be covered with a tarpaulin cloth.how many metres of A tarpaulin of width 96 cm is required to cover 100 such suitcase?
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A suitcase is in the shape of a cuboid .
So, surface area of a cuboid=2(lb+bh+lh),where l=length, b=breadth, h=height of the cuboid
Let the length, breadth and height of the suitcase be l , b, h respectively
Here, l = 80cm , b = 48cm , h = 24cm
Therefore, area=2(80*48+48*24+80*24)cm²
= 2(3840+1152+1920)cm²
= 2*6912cm²
= 13824cm²
Hence, surface area of 100 suitcases= 12160cm²*100
= 1382400 cm²
Also, surface area of the tarpaulin will also be the same
Therefore,required length of tarpaulin
=surface area÷width
= 1382400 cm² ÷ 96cm
= 14400 cm (approx)
= 144 m
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