Question

a suitcase with measures 80cm x 48cm x 24cm is to be covered with a tarpaulin cloth . how many meters of tarpaulin of width 96cm is required to cover 100 such suitcase

Answer 1

Given,

Length of suitcase l = 80cm

Breadth of suitcase b = 48cm

Height of suitcase h = 24cm

As tarpaulin cloth covers the suitcase,

Therefore, Area of cloth required to cover 1 suitcase,

= T. S. A of 1 suitcase

Formula of T. S. A of cuboid :-

2(lb + bh + hl )

= 2( 80cm × 48cm + 48cm × 24cm + 24cm × 80cm)

= 2( 3840 cm² + 1152 cm² + 1920 cm²)

= 2 × 6912 cm²

= 13,824 cm²

Now, we need to find how many metres of tarpaulin cloth of wide 96cm is required to cover 100 such suitcases,

Since, tarpaulin is a rectangle,

So, we need to find the length,

Now,

Area of tarpaulin = 100 × area of 1 suitcase

=> 96 × length = 100 × 13,824

$\sf{\implies \: Length =100 \times \frac{13824}{96} }$

$\sf{ \implies Length = 100 × 144}$

$\sf{\therefore \: Length = 14400cm}$

If converted into metre

$\sf{14400 \times \frac{1}{100} m = 144m}$

Hence, 144m cloth is required.