Question

A suitcase with measures 90 cm x 48 cm x 30cm is to be covered with a

tarpaulin cloth. How many metres tarpaulin of width 94cm is required to

cover 100 such suitcases?​

Answer 1

$\\ \large\sf \: † \: \: \underbrace{\underline{Question:-} }$

A suitcase with measures 90 cm x 48 cm x 30cm is to be covered with a  tarpaulin cloth. How many metres tarpaulin of width 94cm is required to  cover 100 such suitcases?​

$\\ \large\sf \: † \: \: \underbrace{\underline{Answer:-} }$

Given:-

• Dimensions of the suit case = 90 cm × 48 cm × 30 cm
• Width of tarpaulin = 94 cm

To find:-

• How many metres of tarpaulin of width 94 cm is required to cover 100 suitcases of dimensions 90 cm × 48 cm × 30 cm

Solution:-

The suitcase is in the shape of a cuboid and we need to find how much tarpaulin is required to cover it. Therefore, we need to find the total surface area of the cuboid(suitcase).

We know that,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Total Surface Area of a cuboid = 2[lb + bh + hl]

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 2[(90)(48) + (48)(30) + (30)(90)]

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀ ⠀ ⠀ = 2[4320 + 1440 + 2700]

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀ ⠀ ⠀ = 2[8460]

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀ ⠀ ⠀ ⠀ = 16920 cm²

_________________________________________________________

Total Surface Area of 100 suitcases = (16920)(100)

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀ = 1692000 cm²

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀________________________________

Tarpaulin required $= \frac{1692000}{94}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀  = 18000 cm

We know that,

• 1 m → 100 cm
• 1 cm → 0.01 m

∴ 18000 cm → $\frac{18000}{100}$ m

= 180 m

⠀⠀ ⠀ ⠀ ⠀ ⠀ ⠀

∴ 180 m of tarpaulin is required to cover 100 suitcases of dimensions 90 cm × 48 cm × 30 cm

Answer 2

180 m of tarpaulin is required to cover 100 suitcases of dimensions 90 cm × 48 cm × 30 cm.