A suitcase with measures of 80cm×48cm×24cm is to covered with tarpaulin cloth . How many meters of tarpaulin of width 96cm is required to cover 100such suitcase.?
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Answer:
measurements of suitcase :- l =80cm B =48 cm h = 24cm
T. S. A. OF SUITCASE = 2(LB+BH+LH)
=2(80*48+48*24+80*24)
= 2(3840+1152+1920)
= 2(6912)
= 13824 sq. CM
width of tarpaulin = 96 CM ( B)
length of tarpaulin = a
area of tarpaulin required to cover one suitcase = t. s. a. of one suitcase
a*b = 13824
a * 96 = 13824
a = 13824/96
a = 144 cm
there fore length of tarpaulin required to cover 100 suitcase = 144*100
= 14400
= 144 m
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