Question

A suitcase with measures
$80cm \times 48cm \times 24cm$
is to be covered with a tarpaulin cloth . how many meters of tarpaulin of width 96 cm is required to cover 100 such suitcase?​

Answer 1

Answer:

144 m.

Step-by-step explanation:

Total surface area of one suitcase = 2 [80 × 48 + 48 × 24 + 80 × 24] sq.cm. = 2 [3840 + 1152 + 1920] sq.cm. = 2 × 6912 sq.cm. = 13824 sq.cm

Therefore , total surface area of 100 such suitcase = 100 × 13824 sq.cm. = 1382400 sq.cm

Suppose the length of the required tarpaulin => x cm

Then the area of the tarpaulin = x × 96 sq.cm

Now , x × 96 = 1382400

=> x = 1382400/96 = 14400 cm => 144 m.

Answer 2

Step-by-step explanation:



Solution:

Let the length of the tarpaulin cloth = x cm

Since, the suitcase is cuboidal in shape,

Total surface of the suitcase = 2(lb + bh + hl) .... (1)

Here, l = 80cm, b = 48cm, h = 24cm

Thus, substituting the values in equation (1) we get,

= 2 [(80 × 48) + (48 × 24) + (24 × 80)] cm²

= 2 [3840 + 1152 + 1920] cm²

= 13824 cm²

Total surface area of 100 suitcases

= 100 × 13824 m²

= 1382400 cm²

Area of the tarpaulin cloth required = Total surface area of 100 suitcases = 1382400 cm²

Area of the required tarpaulin cloth = Length × Breadth

1382400 cm² = x × 96 cm

x = 1382400/96 cm = 14400 cm

x = 144 m

Thus, the length of the tarpaulin cloth required is 144 m.

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