Question

A sulphuric acid solution containing 571.4 g of h2sO4 per litre of solution has a density of 1.329 g / cm3.. Calculate the molality of H2SO4 in this solution

Answer 1

Answer:

H3SO4???

H2SO4

mass of the solution = d x V = 1.329 x 1000 = 1329 g

%C = mass solute / d V x(100)

The mass % for the density of the solution does not correspond

to 1.329 g/mL (density) it corresponds to 35.9%

m =%CDV

m = 0.359 x 1.329 x 1000 mL = 477.11 (mass solute)

477.11/98 g/mol = 4.87 mol