A sulphuric acid solution contains 98% (m/v) H2SO4. The density of the solution is 1.98 g/cm^3. The molarity and molality of the solution are
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Answer:
Density=1.98g
weight of H
2
SO
4
=98g
weight of solution=100g
∴volume of solution=
1.98
100
=50.5cm
3
weight of solvent(water)=100-98=2g
Molecular weight of H
2
SO
4
=98g/mol
∴ no of moles in 98g=
molarmass
givenmass
=
w
m
=
98
98
=1mol
Molality =
weightofsolvent in gram
no. ofmoles ofsolute
X1000
=
2
1
X1000=500mol/kg
Molarity =
volumeofsolution in ml
noofmolesofsolute
X1000
=
50.5
1
X1000=19.8mol/LH
2
SO
4
is the answer.
Explanation:
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