Question

a sum$360 is divided between 96 students.each student belongs to ecectly of two groups a and b if each student in group a got $2.40​

Answer 1

$\underline{\textsf{Given:}}$

$\textsf{A sum 360 is divided between 96 students.each student belongs}$

$\textsf{to ecectly of two groups A and B if each student in group A got}$

$\textsf{2.40 and each student group B got 4.80}$

$\underline{\textsf{To find:}}$

$\textsf{Number of students in group B}$

$\underline{\textsf{Solution:}}$

$\textsf{Let x and y be the number of students in group A and B respectively}$

$\textsf{As per given data,}$

$\mathsf{x+y=90}$......(1)

$\mathsf{2.4x+4.8y=360}$

$\implies\mathsf{x+2y=150}$....(2)

$\textsf{Now, we solve (1) and (2)}$

$\mathsf{x+y=90}$........(1)

$\mathsf{x+2y=150}$........(2)

$\mathsf{(2)-(1)\implies}$

$\mathsf{2y-y=150-90}$

$\implies\boxed{\mathsf{y=60}}$

$\mathsf{(1)\implies\;x+60=90}$

$\implies\boxed{\mathsf{x=30}}$

$\underline{\textsf{Answer:}}$

$\textsf{Number of students in group B is 60}$

$\underline{\textsf{Find more:}}$

100 pencils are to be kept inside 3 types of boxes a,b,c if 5 boxes of type a and 3 boxes of type b,2 boxes of type c are used 6 pencils are left out if 3 boxes of type a,5 boxes of type b 2 boxes of type c 2 pencils are left out if2 boxes of type a,4 boxes of types,4 boxes oftype c there is space for 4 more pencil find the no of pencils that each box can hold

https://brainly.in/question/17298932

Answer 2

SOLUTION

GIVEN

• A sum $ 360 is divided between 96 students.

• Each student belongs to exactly of two groups A and B

• Each student in group A got $ 2.40

• Each student in group B got $ 4.80

TO DETERMINE

The number of students in group B

EVALUATION

Here it is given that total number of students = 96

Suppose there are N students in Group A

∴ The number of students in Group B = 96 - N

It is stated that each student in group A got $ 2.40

∴ Total amount of money Group A got

= $ ( N × 2.40 )

Again each student group B got $ 4.80

∴ Total amount of money Group B got

= $ [ ( 96 - N ) × 4.80 ]

Again The total amount of money distributed = $ 360

Hence by the given condition

$\sf{(N \times 2.40) + (96 - N) \times 4.80 = 360}$

$\sf{ \implies \: (N + 192 - 2 N) \times 2.40 = 360}$

$\displaystyle \sf{ \implies \: (192 - N) = \frac{360}{2.40} }$

$\displaystyle \sf{ \implies \: (192 - N) = \frac{36000}{240} }$

$\displaystyle \sf{ \implies \: (192 - N) = 150 }$

$\displaystyle \sf{ \implies \: N =192 - 150 }$

$\displaystyle \sf{ \implies \: N = 42 }$

∴ The number of students in Group A = 42

∴ The number of students in Group B

$\sf{ = 96 - 42}$

$\sf{ = 54}$

FINAL ANSWER

The number of students in Group B = 54

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