a sum amounted to Rupees 2486 with the interest of 13 % per annum then what is the sum
Answers
Step-by-step explanation:
Hєч mαtє✌✌
hєrє íѕ ur αnѕwєr ✍✍✍✍✍✍
●INTEREST = Interest is the price paid by a borrower for the use of a lender's money.
TYPE OF INTEREST----- there are 2 type of interest--
●Simple Interest
●Compound Interest
♥Simple Interest = Simple interest is the computed on the principal for the entire period of borrowing.
Formula -----
I = Pit
A = P + I
I = A - P
here
I = Amount of Interest
P = principal ( initial value of an investment)
A = Accumulated amount ( Final value of an investment)
i = Annual interest rate in decimal
t = time in years
♥Compound Interest = compound interest as the interest that accrues when earnings for each specified period of time added to the principal thus increasing the principal base on which subsequent interest is compound.
Formula -
A = p (1 + i)^n
where,
i = Annual rate of interest
n = Number of conversion period per year
INTEREST = An - P
or
= P ( 1 + i)^n - P
Let, move to ur Question -----
ɢɪᴠᴇɴ ----
ᴩ = ???
ʀ = 13%
ɴ = 5 Yᴇᴀʀꜱ
A = 66,000
we know that ----
A = P (1 + it )
₹ 66,000 = P [1 +(13 /100) 5]
₹66,000 = P ( 1 + 0.13×5)
₹66,000 = P ( 1 + 0.65)
₹66,000 = P (1.65)
₹66,000 /1.65 = ᴩ
P = ₹ 40,000
ᴜ ᴄᴀɴ ʀᴇᴄʜᴇᴄᴋ ᴛʜᴇ ᴀɴꜱ ---
ꜱɪ = ᴩʀᴛ /100
= ₹40,000 ×10×5/100
= ₹26,000
ᴀ = ᴩ + ɪɴᴛ
= 40,000 + 26,000
= 66,000
ʜᴏᴩᴇ ɪᴛ ʜᴇʟᴩꜱ ᴜ ☺☺
ꜰᴇᴇʟ ꜰʀᴇᴇ ᴛᴏ ᴀꜱᴋ questions
Answer:
Let the sum be x
A/q
x + 13% of x = 2,486
113x=248600
x= 248600÷113
x= 2200