Question

a sum at simple interest at 131/2% per annum amounts to Rs. 2502.50 after 4years. Find the sum.

Answer 1

Hi ,

rate of interest = r = 13 1/2 % = 27/2 %

time ( t ) = 4 years

Amount ( A ) = Rs 2502.5)

Let principal = P

P( 1 + tr/100 ) = A

P[ 1 + ( 4 × 27)/( 2 × 100 ) ] = 2502.50

P [ 1 + 27/50 ] = 2502.50

P [ 77/50 ] = 2502.50

P = ( 2502.50 × 50 )/ 77

P = Rs 1625




simple interest = A - P

s.i = 2502.50 - 1625

s.i = Rs 877.50

I hope this helps you.

: )

Answer 2

hye

================================

r% = 131/2% = 65.5%

time= 4 years

amount = 2502.50

=>we know that s.i + p =a

=>$p + [ \frac{p*r*t}{100} ] = 2502.50$

$p + [ \frac{p*65.5*4}{100} ] = 2502.50$

=>$p + \frac{262p}{100} = 2502.50$

=>$\frac{362p}{100} = 2502.50$

=>362p = 2502.50 *100

=>362p = 250250

=>p = 250250 / 362

=> p = 691.28 rs

======================

hope it helps u.............