A sum becomes 1.6 times of itself in five years at simple rate of interest. Find rate of interest per annum
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Answered by
4
Answer:
Step-by-step explanation:
Let the principal be P
Then, according to the question let the simple interest be S.I= P/2
Let rate of interest be r
Here time, t= 5 years
We know, S.I = P*r*t/100
=> P/2= P*r*5/100
=> R= 10
Hence the rate of interest would be 10%
Answered by
19
Let sum = P,
rate of interest = r % per annum
we know , S.I = P × r × t/100
where t is time ,
also , A = P + S.I
it is given, that A = 1.6P and t = 5yrs
1.6P = P + P × r × 5/100
1.6P - 1P = Pr/20
0.6P = Pr/20
0.6 × 20 = r
r = 12 % per annum.
rate of interest = r % per annum
we know , S.I = P × r × t/100
where t is time ,
also , A = P + S.I
it is given, that A = 1.6P and t = 5yrs
1.6P = P + P × r × 5/100
1.6P - 1P = Pr/20
0.6P = Pr/20
0.6 × 20 = r
r = 12 % per annum.
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