A sum compounded annually becomes 25/16
times of itself in two years. Determine the rate of interest per annum.
Answers
Answer:
Answer:P→
Answer:P→ 16
Answer:P→ 1625
Answer:P→ 1625
Answer:P→ 1625 p in two years
Answer:P→ 1625 p in two years∴
Answer:P→ 1625 p in two years∴ 16
Answer:P→ 1625 p in two years∴ 1625
Answer:P→ 1625 p in two years∴ 1625
Answer:P→ 1625 p in two years∴ 1625 p=p(1+
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r )
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 (
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 4
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 )
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r )
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 4
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45 =1+
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45 =1+ 100
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45 =1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45 =1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45 =1+ 100r
Answer:P→ 1625 p in two years∴ 1625 p=p(1+ 100r ) 2 ( 45 ) 2 =(1+ 100r ) 2 ⇒ 45 =1+ 100r r=25%.