a sum if money is shared among 3 brother the eldest receive 7/13 of it and the next receive 2/3 of the remainder
a) find the fraction of money the youngest brother receive
b) if the sum of money is 65 dollar find the share of the younger brother
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Answer:
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Step-by-step explanation:
a) Let the total money be x, which 7s shared between three brothers
The eldest receives 7/13 of it
7/13 of x
= 7x/13
and the next receives 2/3 of the remainder
Remaining money after eldest share
x - 7x/13
=(13x - 7x)/13
= 6x/13
Next get 2/3 of 6x/13
= 2/3 × 6x/13
= 12x / 39
b) Whole part (a) comes here and continues .....
The youngest brother received $6
7x/13 + 12x/39 + $6 = x
(21x + 12x)/39 = x - 6
33x/39 = x - 6
Cross multiplications
33x = 39 (x - 6)
33x = 39x - 234
33x - 39x = - 234
-6x = -234
x = 234/6
x = 39
The total money is $39
Answer the total money is $39
Now checking the correctness of answer by distributing the derived money $39 among three brothers.
Eldest received 7/13 of 39 = $21
Second brother received 2/3 of (39 - 21) = 2/3 × 18 =$12
Youngest brother received $6
Total money = $21 + $12 + $6= $39
Means answer is correct