A sum lent out at simple interest becomes ₹4480 in 3 years and ₹4800 in 5 years. Find the sum and the rate of interest.
Answers
Answer:
P=4000
R = 4%
Step-by-step explanation:
Let the sum be "p"
and rate of interest " r"
after 3 yrs the sum = ( p × r ÷100 ×3 )+p
= (3 p r ÷ 100) +p
= 4480................given.....(1)
after 5 yrs the sum = ( p × r ÷100 ×5 )+p
= (5p r ÷ 100) +p
= 4800 ..............given ......(2)
Subtracting (1) from (2) we get
(5pr÷100) +p = 4800
- [(3or ÷ 100) +p ] = - 4480
2pr÷100 = 320
pr = 320 ×100 ÷2
= 16,000
substituting in equation (2) we get
[ ( 5 × 16000 ÷ 100 ) + p ] = 4800
800 + p = 4800
p = 4800 -800
= 4000
again substituting this value in eq (2) we get
(5pr÷100) +p = 4800
( 5×4000×r÷100) +4000 = 4800
200r = 4800 -4000
= 800
r = 800 ÷ 200
= 4
Principle = 4000
Rate of interest = 4 %
HOPE IT HELPS!!
Step-by-step explanation:
We know that,
Amount,A=P+
100
PNR
For the first situation,
3,825=P+
100
P×4×R
=>3,825=P+
100
4PR
--- (1)
And for the second situation,
4,050=P+
100
P×6×R
=>4,050=P+
100
6PR
--- (2)
Now, subtracting eqn 1 from 2, we get
225=
100
2PR
=>PR=11,250
Putting the value of PR in equation 1, we get
=>3,825=P+
100
4×11,250
=>3,825=P+
100
4×11,250
=>3,825=P+450
=>P=3,375
And since PR=11,250
=>R= 3,375
11,250