Question

A sum of 1000 is invested at 8% simple
interest per annum. Calculate the interest
at the end of 1, 2, 3, ... years. Is the
sequence of interests an AP? Find the
interest at the end of 30 yr.​

Answer 1

Answer:

2400

Step-by-step explanation:

given,

   principal = 1000

    rate of interest = 8%

      number of years = 1 year

     SI = Pnr/100 = 1000 x 1 x 8/100 = rs.80

when n = 2 years , SI = 1000 x 2 x 8/100 = rs.160

when n = 3 years , SI = 1000 x 3 x 8/100 = rs.240

the sequence is  

    80 , 160 , 240 ,...

this is in AP as a first term = 80 , d , common difference = 80

interest at the end of 30 years , t30=a+(n-1)d

                                                = 80+(30-1)80

                                                = 80+29(80)

                                                = 80+2320

                                                = 2400

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