Question

A sum of 1000 is invested at 8% simple interest per year. i) Calculate the interest at the end of each year. ii) Do these interests form an A.P. ? iii) If so, find the interest at the end of 30 years.
​

Answer 1

please mark me as brilliant

Answer 2

$\boxed{\tt{amount = 1000}}$

$\boxed{\tt{Interest =1000 \times \frac{8}{100} = 80 }}$

$\boxed{\tt{Interest \: after \: 2years \: = 2 \times1000 \times \frac{8}{100} = 160 }}$

$\boxed{\tt{Interest \: after \: 3 \: years = 3 \times 1000 \times \frac{8}{100} = 240 }}$

$\boxed{\tt{I _{3} - I_{2} = I _{2} - I_{1} }}$

$\boxed{\tt{80 = 80}}$

$\boxed{\tt{Thus, \: interest \: from \: A.P}}$

$\boxed{\tt{ I_{ 30}=1000 \times \frac{8}{100} \times 30 =2400 }}$

$\boxed{\tt{The \: interest \: at \: end \: of \: 30 \: years \: is \: Rs.2400 }}$

I am Fine Had ur dinner