a sum of 1000 ₹ is invested of at 8% simple interest per year calculate the interest at the end of each year do this interests for 1st 2nd and 3rd years from an AP if so find the total interest to be paid for 30years making the use of this fact
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Answer:
given,
principal=1000
rate of interest=8%
number of years=1 year
SI=Pnr/100=1000x1x8/100=rs.80
when n=2 years,SI=1000x2x8/100=rs.160
when n=3years,SI=1000x3x8/100=rs.240
the sequence is
80,160,240,..........
this is in AP as a,first term=80,d,common difference=80
interest at the end of 30 years,t30=a+(n-1) =80+(30-1)80
=80+29(80
=80+2320
=2400
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