Math, asked by Manjot6825, 1 year ago

A sum of 10000 is lent partly at 8% and the remaining at 10%per annum. if the yearly interest on the average is 9.2%,the two parts are?

Answers

Answered by sunilkumar5
2
4000 and 6000...................
Answered by Anonymous
16
Hey mate!

Here's your answer!!

Let the sum lent at 8% is x, then sum lent at 10% is (10000 - x)

x \times  \frac{8}{100}  \times 1 + (10000 - x) \times  \frac{10}{100}  \times 1
 = 10000 \times  \frac{92}{100} \times 1
   = \frac{8x}{100}   +  \frac{10(10000 - x}{100}  = 920
8x + 100000 - 10x = 92000
➡ -2x + 100000 = 92000
➡ -2x = 92000 - 100000
➡ -2x = -8000
➡ x = 4000

Amount lent at 8% = ₹4000
Amount lent at 10% = (10000 - 4000) = ₹6000

hope \: it \: helps \: you.
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