*. A sum of 2,500 is distributed among
X, Y and Z in the ratio 1/2:3/4:5/6. What is
the difference between the maximum
share and the minimum share?
(a) Rs300
(b) Rs350
(c) Rs400
(d) Rs 450
Answers
Step-by-step explanation:
X : Y : Z = 1/2 x : 3/4 x : 5/6 x
X+Y+Z = 2500/-
1/2x+3/4x+5/6x = 2500
(6x+9x+10x) ÷ 12 = 2500
25x = 2500 × 12
25x = 30000
x = 1200/-
X = 1/2 ×1200 = 600/-
Y = 3/4 × 1200 = 900/-
Z = 5/6 × 1200 = 1000/-
Max share - Min share = 1000 - 600 = 400₹
Given : A sum of 2,500 is distributed among
X, Y and Z in the ratio 1/2 : 3/4 : 5/6
To Find : difference between the maximum share and the minimum share
Solution:
Share of X = a/2
Share of Y = 3a/4
Share of Z = 5a/6
Total Share = a/2 + 3a/4 + 5a/6
= a(6 + 9 + 10)/12
= 25a/12
25a/12 = 2500
=> a = 1200
Share of X = a/2 = 1200/2 = 600
Share of Y = 3a/4 = 3(1200)/4 = 900
Share of Z = 5a/6 = 5(1200)/6 = 1000
Maximum share = 1000
Minimum Share = 600
Difference = 1000 - 600 = 400
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