Math, asked by ruchirokade, 1 month ago

A sum of 2400 to be distributed among 6 top
participants of a contest. If each prize amount is 40 less than
its preceding amount, find the highest prize amount​

Answers

Answered by Dhruv4886
0

The highest prize money is 500 Rs

Given:

A sum of 2400 to be distributed among 6 top participants of a contest

If each prize amount is 40 less than its preceding amount

To find:

Find the highest prize amount​

Solution:

Given that each prize money is 40 less than the preceding amount

Let x be the highest amount and 1st price

Then the 2nd prize must 40 less than x

and third prize must be 40 less than 2nd prize

In this pattern the 6 prizes amounts will be as shown below

x, x - 40, x - 2(40), x- 3(40), x - 4(40), x - 5(40)  

As we know sum of all these are equals to 2400  

⇒  x+ x - 40 + x - 2(40) + x- 3(40) + x - 4(40) + x - 5(40) = 2400  

⇒ 6x - 40 - 80 - 120 - 160 - 200 = 2400

⇒ 6x - 600 = 2400

⇒ 6x = 3000

⇒ x = 500

Therefore, the highest prize money x = 500 Rs  

#SPJ2

Answered by sourasghotekar123
0

Answer: The amount of highest prize is 500.

Step-by-step explanation:

According to the question,

Value of the given 6 prizes are in A.P.

Sum of all prizes (S) = 2400

common diffrence (d) = -40

Number of prizes(n) = 6

on applying A.P.  formula of sum

⇒S=\frac{n}{2} [2a+(n-1)d]

2400=\frac{6}{2} [2a+(6-1)(-40)]

2400=3[2a-200]\\2400=6a-600\\

divide the equation by 6

400=a-100

transfer 100 from other side

400+100=a

a=500\\

The highest prize amount is 500rs.

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