Question

A sum of 2500 rupees is borrowed at a rate of 12% per annum for 3 years find the simple interest on this summer and also the amount to be paid at the end of 3 years​

Answer 1

Answer:

1. Simple Interest = Rs 900
2. Amount = Rs 3400

Step-by-step explanation:

Given that:

• Sum of money = Rs 2500
• Rate of Interest = 12% per annum
• Time period = 3 years

To Find:

1. Simple Interest.
2. Amount.

Formula used:

• S.I = (P × R × T)/100
• A = P + S.I

Here,

• S.I = Simple Interest
• P = Sum of money
• R = Rate of Interest
• T = Time period
• A = Amount

Finding the simple interest:

⇒ S.I = (2500 × 12 × 3)/100

⇒ S.I = (90000)/100

⇒ S.I = 900

∴ Simple Interest = Rs 900

Finding the amount:

⇒ A = 2500 + 900

⇒ A = 3400

∴ Amount = Rs 3400

Answer 2

Question:-

• A sum of 2500 rupees is borrowed at a rate of 12% per annum for 3 years find the simple interest on this summer and also the amount to be paid at the end of 3 years.

To Find:-

• Find the simple interest and amount.

Solution:-

Here ,

$\underline{\underline{\sf{ Formula Used}}} :$

$\tt\implies \: S.I = \dfrac { PTR } { 100 }$

Substituting Values:-

$\tt\implies \: S.I = \dfrac { 2500 \times 12 \times 3 } { 100 }$

$\tt\implies \: S.I = \dfrac { 90000 } { 100 }$

$\tt\implies \: S.I = 900$

Finding the Amount:-

$\tt\implies \: A = 2500 + 900$

$\tt\implies \: A = 3400$

Hence ,

• Simple Interest is 900

• Amount is 3400