Question

A sum of 2500 rupees is borrowed at a rate of 12% per annum for 3 years find the simple interest on this summer and also the amount to be paid at the end of 3 years​

Answer 1

Answer:

SI= PRT/100

P principal

R Rate

T Time

2500×12×3÷100

00 cancel

remaining

25×12×3

SI =900

Amount= SI+Principal

2500+900=3400

Answer 2

Answer:

P (Principal amount) = ₹ 2500

N (No. of years) = 3

R (Rate of interest) = 12 % P.A.

S.I. (Simple interest) = ?

A (Amount) = ?

$S.I = \frac{PNR}{100} \\ = \frac{2500 \times 3 \times 12}{100} \\ = \frac{25 \times 3 \times 12}{1} \\ = 75 \times 12 \\ = 900$

Therefore, simple interest = ₹ 900

$A = P + S.I. \\ = 2500 + 900 \\ = 3400$

Therefore, amount = ₹ 3400