Question

A sum of 280 is to be used to give four prizes. If
each prize is 20 less than its preceding prize,
find the value of each of the prizes.​

Answer 1

let the prizes be a, a+d, a+2d , a + 3d

d = 20  (from qn)

a + a+d + a+2d  + a + 3d = 280

4a + 6d = 280

4a + 6(20) = 280

4a + 120 = 280

4a = 160

a = 160/4 = 40

therfor the prizes are

a= 40 4th prize

a + d =  40 + 20 = 60 3rd prize

a + 2d = 40 + 40 = 80  2nd prize

a + 3d = 40 + 60 = 100 1st prize

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Answer 2

Answer:

1st prize=Rs.100

2nd prize=Rs.80

3rd prize=Rs.60

4th prize=Rs.40

Step-by-step explanation:

let amt for 1st prize=x

therefore, amt for 2nd prize = x-20

               amt for 3rd prize = x-20-20 = x-40

               amt for 4th prize = x-40-20 = x-60

therefore,

x+(x-20)+(x-40)+(x-60)=280

=>4x -120=280

=>x=100

therefore, 

1st prize=Rs.100

2nd prize=Rs.80

3rd prize=Rs.60

4th prize=Rs.40