A sum of 280 is to be used to give four prizes. If
each prize is 20 less than its preceding prize,
find the value of each of the prizes.
Answers
Answered by
2
let the prizes be a, a+d, a+2d , a + 3d
d = 20 (from qn)
a + a+d + a+2d + a + 3d = 280
4a + 6d = 280
4a + 6(20) = 280
4a + 120 = 280
4a = 160
a = 160/4 = 40
therfor the prizes are
a= 40 4th prize
a + d = 40 + 20 = 60 3rd prize
a + 2d = 40 + 40 = 80 2nd prize
a + 3d = 40 + 60 = 100 1st prize
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Answered by
2
Answer:
1st prize=Rs.100
2nd prize=Rs.80
3rd prize=Rs.60
4th prize=Rs.40
Step-by-step explanation:
let amt for 1st prize=x
therefore, amt for 2nd prize = x-20
amt for 3rd prize = x-20-20 = x-40
amt for 4th prize = x-40-20 = x-60
therefore,
x+(x-20)+(x-40)+(x-60)=280
=>4x -120=280
=>x=100
therefore,
1st prize=Rs.100
2nd prize=Rs.80
3rd prize=Rs.60
4th prize=Rs.40
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