Question

A sum of ₹2800 is to be used to award four prizes. If each prize after the first is ₹200 less than the preceding prize, find the value of each of the prizes. ​

Answer 1

Answer:

1000,800,600 and 400

Step-by-step explanation:

let the four prizes be a,b,c and d

let the prize of a be x

b = x-200

c = x-200-200 = x-400

d = x-200-200-200 = x-600

ATQ,

a+b+c+d = 2800

x + x-200+ x-400  + x-600 = 2800

4x -1200 = 2800

4x = 2800+1200

x = 4000/4 = 1000

value of prize

a = x = 1000

b = x-200 = 1000-200 = 800

c = x-400 = 1000-400 = 600

d = x-600 = 1000-600 = 400

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Answer 2

Let the money first one gets equal to x then,

Money second person got x-200

Money Third person got x-400

Money fourth person for equals x-600

Therefore,

x+x-200+x-400+x-600=2800

4x-1200=2800

4x=4000

x=1000

Therefore money each person got

1st person=x=1000

2nd person =x-200=800

3rd person =x-400=600

4th person =x-600=400