A sum of ₹2800 is to be used to award four prizes. If each prize after the first is ₹200 less than the preceding prize, find the value of each of the prizes.
Answers
Answered by
17
Answer:
1000,800,600 and 400
Step-by-step explanation:
let the four prizes be a,b,c and d
let the prize of a be x
b = x-200
c = x-200-200 = x-400
d = x-200-200-200 = x-600
ATQ,
a+b+c+d = 2800
x + x-200+ x-400 + x-600 = 2800
4x -1200 = 2800
4x = 2800+1200
x = 4000/4 = 1000
value of prize
a = x = 1000
b = x-200 = 1000-200 = 800
c = x-400 = 1000-400 = 600
d = x-600 = 1000-600 = 400
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Answered by
8
Let the money first one gets equal to x then,
Money second person got x-200
Money Third person got x-400
Money fourth person for equals x-600
Therefore,
x+x-200+x-400+x-600=2800
4x-1200=2800
4x=4000
x=1000
Therefore money each person got
1st person=x=1000
2nd person =x-200=800
3rd person =x-400=600
4th person =x-600=400
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