Question

A sum of 2800rupees is to be used to award four prices. If each prize after the first is
200rupees less than the preceding price, find the value of each of the prizes.
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Answer 1

Answer:

₹1000 , ₹800 , ₹600 , ₹400

Step-by-step explanation:

The value of each prize forms an Arithmetic Progression.

Sum of prizes = 2800 ₹

common difference d = -200 ₹

number of prizes n = 4

Sum of terms = (n/2)×(2a + (n-1)d )

2800 = (4/2)×(2a + (4-1)(-200) )

2800 = 2(2a - 600)

1400. = 2a - 600

2a. = 2000

a = 1000

The value of prizes are ₹1000 , ₹800 , ₹600 , ₹400.

PLEASE MARK MY ANSWER AS BRAINLIEST.

Answer 2

Answer:

Let the first prize be x

so other three prizes are x-200,X-400&x-600

so by the condition given in the question

x+x-200+x-400+x-600=2800

4x-1200=2800

4x=4000

x=1000