A sum of 3.75 was paid in 25 - paise, 10-paise and 6 prise coins. The number of
10 paise coins was four times the number of 25 paise coins and twice the number of
5 paise coins, how many were there of each?
Answers
Answer:
ANSWER
Let the number of 10 paisa coins be x, number of 25 paisa coin=
4
x
Number of 5 paisa coin=
2
x
According to the given problem,
⇒
100
10x
+
4
x
×
100
25
+
2
x
×
100
5
=3.75
⇒
100
10x
+
400
25x
+
200
5x
=
100
375
⇒
400
40x
+
400
25x
+
400
10x
=
100
375
⇒
400
40x+25x+10x
=
100
375
⇒
4
75x
=
1
375
∴x=
75
1500
=20
Number of 10 paisa coins=20
Number of 25 paisa coins=5
Number of 5 paisa coins=10
Answered By
toppr
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ANSWER
Let the number of 10 paisa coins be x, number of 25 paisa coin=
4
x
Number of 5 paisa coin=
2
x
According to the given problem,
⇒
100
10x
+
4
x
×
100
25
+
2
x
×
100
5
=3.75
⇒
100
10x
+
400
25x
+
200
5x
=
100
375
⇒
400
40x
+
400
25x
+
400
10x
=
100
375
⇒
400
40x+25x+10x
=
100
375
⇒
4
75x
=
1
375
∴x=
75
1500
=20
Number of 10 paisa coins=20
Number of 25 paisa coins=5
Number of 5 paisa coins=10
Step-by-step explanation:
Answer: number of 5, 10 and 25 paise coins respectively are 10, 20, 5
Step-by-step explanation:
Number of 25 paise coins be x
Then, no. of ten paise coins will be 4x
and no. of 5 paise coins will be 4x/2 = 2x
Now, 25 paise =1/4 rupee
value of 1/4 rupee coins = x/4
value of 10 paise coins or 1/10 rupee coins will be 4x/10 = 2x/5
Now, Value of 5paise or 1/20 rupee coin = 2x/20 =x/10
Now, given, x/4 + 2x/5 + x/10 = 3.75
= 5x/20 + 8x/20 +2x/20 = 3.75
15x/20 = 3.75
3x/4 = 15/4
4 will get canceled
and we will get
3x =15 x =5
So, number of 5, 10 and 25 paise coins respectively are= 5*2, 5*4 5*1
= 10, 20, 5