A sum of ₹ 3000 is lent for 2 years at the rate of 6%. Find the principal for 2nd year.
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Answers
Answered by
3
Answer:
₹3370.80
Step-by-step explanation:
P = ₹3000
n (number of years) = 2 years
R = 6 %
A = P (1+R/100)^n
= 3000 (1 + 6/100)^2
= 3000 x 106/100 x 106/100
= 3 x 106 x 106/10
= ₹3370.80
So therefore amount at the end of 1st year and beginning of 2nd year js ₹3370.80
Answered by
1
given,
P = ₹3000
n (number of years) = 2 years
R = 6 %
A = P (1+R/100)^n
= 3000 (1 + 6/100)^2
= 3000 x 106/100 x 106/100
= 3 x 106 x 106/10
= ₹3370.80
So therefore amount at the end of 1st year and beginning of 2nd year js ₹3370.80
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