Math, asked by charith9, 6 months ago

A sum of 3000 is to be even the form of 63 prizes. If the prize money is either 100 or 25. Find the ber of prizes of each type​

Answers

Answered by ankitakeshri740
0

Answer:

Let no. of Rs 100 prizes be n and 25 prizes be (63-n)

100n + (63-n)25 = 3000

75n = 3000-1575

75n = 1425

n = 19

No. Of Rs 100 prizes are 19 and Rs 25 prizes are (63-19) = 44

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