Math, asked by abcde8551, 1 year ago

A sum of ₹3000 is to be given in the form of 63 prizes.If the prize money is either ₹100or₹25.Find the number of prizes of each parts

Answers

Answered by md2181336
5

Answer:

Step-by-step explanation:

Let the no. Of rs100 be x

Rs25 be y

According to the question,

X+y=63____eq (1)

And,100x+25y=3000____eq(2)

Solving eq 1 and 2 we get,

X=19

Y=44

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Answered by Anonymous
1

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Given the sum of prizes money = 3000

➡ Total number of prizes = 63

➡ number of prizes cost = 100x

➡ number of prize of cost = 25

will be 63 - x

From the problem we can write

=> x × 100 (63 - x) 25 = 3000

=> 100x + 1575 - 25x = 3000

(transporting) 1575 on L.H.S to R.S.H

we get

=> 100x - 25x = 3000 - 1575

=> 75x = 1425

=> x = 1425÷ 75

=> x = 19

number of 100 prizes = 19

number of 25 prizes = 63 - 19

➡ answer = 44

Hope it helps!!

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