Question

A sum of 3700 is divided among A, B and C such that B`s share is thrice of A`s share and C`s share is 200 more than B`s share. Find the share of A.
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Answer 1

let's see

B= 3A

A=A

C= 200+ B

let's substitute b in C's equation

C= 200+3A

now we have everything in A's

so 3A + A + (200+3A) =3700

7A +200 = 3700

7A= 3500

A= 3500/7

A= 500

A's share = 500

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Answer 2

The share of A is Rs. 500.

Step-by-step-explanation:

We have given that,

A sum of 3700 is divided among A, B and C.

∴ Sum of shares of A, B and C = 3700

⇒ A + B + C = 3700

⇒ A = 3700 - B - C - - - ( 1 )

From the first condition,

B's share = 3 * A's share

⇒ B = 3A

⇒ B = 3 * ( 3700 - B - C )

⇒ B = 11100 - 3B - 3C

⇒ B + 3B = 11100 - 3C

⇒ 4B = 11100 - 3C - - - ( 2 )

From the second condition,

C's share = B'share + 200

⇒ C = B + 200

By using this value in equation ( 2 ), we get,

4B = 11100 - 3C - - - ( 2 )

⇒ 4B = 11100 - 3 ( B + 200 )

⇒ 4B = 11100 - 3B - 600

⇒ 4B + 3B = 11100 - 600

⇒ 7B = 10500

⇒ B = 10500 ÷ 7

⇒ B = 1500

⇒ B's share = 1500 Rs.

Now, by using this value in equation ( 1 ),

A = 3700 - B - C - - - ( 1 )

⇒ A = 3700 - 1500 - ( B + 200 )

⇒ A = 3700 - 1500 - ( 1500 + 200 )

⇒ A = 2200 - 1700

⇒ A = 500

⇒ A's share = 500 Rs.

∴ The share of A is Rs. 500.